8y^2-30y+27=2

Solution for 8y^2-30y+27=2 equation:

8y^2-30y+27=2

We move all terms to the left:

8y^2-30y+27-(2)=0

We add all the numbers together, and all the variables

8y^2-30y+25=0

a = 8; b = -30; c = +25;
Δ = b2-4ac
Δ = -302-4·8·25
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-10}{2*8}=\frac{20}{16}
=1+1/4
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+10}{2*8}=\frac{40}{16}
=2+1/2
$